Steel Buildings in Europe

Part 5: Joint Design 5 – 103 To ensure that the effective area fits on the base plate: h + 2 c < h p b + 2 c < b p 6.3 Base plate thickness eff p 2 + c t f A c t Basic requirement: t p ≥ t p,min t p,min = yp M0 jd 3 f f c  [Reference 3] where: f yp is the yield strength of the base plate f jd = 3 2  f cd f cd = c ck cc   f  , α cc ,  c , f ck , and c are as defined previously.