Steel Buildings in Europe

Title 5.4 Worked Example – Column Splice 8 of 8 5 – 100 Therefore there is no long joint effect. Total thickness of flange pack, t pa = 30mm > 6, 7 3  d mm Therefore F v,Rd must be multiplied by a reduction factor β p . β p = pa 8 3 9 t d d  = 8 20 3 30 9 20     = 0,72 For M20 8.8 bolts, F v,Rd = 3 10 1,1 245 0, 72 0, 6 800      = 77 kN Bearing resistance Bearing resistance, F b,Rd = Mu u,p p 1 b   dt f k Table 3.4 For edge bolts, k 1 =        min 2,8 1,7; 2,5 0 2 d e =        1,7; 2,5 22 min 2,8 55 =   min 5,3; 2,5 = 2,5 For end bolts α b =         ; 1,0 ; 3 min u,p ub 0 1 f f d e =        ; 1,0 430 ; 800 3 22 min 40 =   min 0,61; 1,86; 1,0 = 0,61 For inner bolts, α b =          ; 1,0 0,25; 3 min u,p ub 0 1 f f d p =         ; 1,0 430 0,25; 800 3 22 160 min =   min 2,17; 1,86; 1,0 = 1,0 End bolts, F b,Rd,end =   b,Rd min F = 3 10 1,1 2,5 0, 61 430 20 12       = 143kN Inner bolts, F b,Rd,inner =   max b,Rd F = 3 10 1,1 2,5 1, 0 430 20 12       = 235 kN Thus F v,Rd <   min b,Rd F F Rd = n fp  F v,Rd = 4  77 = 308 kN F tie = 86 kN ≤ 308 kN, OK